"if (nxt)" is always true, as it was checked in the while's condition.
io_wq_current_is_worker() is unnecessary, as non-async callers don't
pass nxt, so io_queue_async_work() will be called for them anyway.
Signed-off-by: Pavel Begunkov <asml.silence@gmail.com>
Signed-off-by: Jens Axboe <axboe@kernel.dk>
nxt->flags |= REQ_F_LINK;
}
- /*
- * If we're in async work, we can continue processing the chain
- * in this context instead of having to queue up new async work.
- */
- if (nxt) {
- if (io_wq_current_is_worker())
- *nxtptr = nxt;
- else
- io_queue_async_work(nxt);
- }
+ *nxtptr = nxt;
break;
}