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Updated to support compiler intrinsics properly. I had to comment out some of the...
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e1f414b6 1/** @file\r
2 Math worker functions.\r
3\r
4 Copyright (c) 2006, Intel Corporation<BR>\r
5 All rights reserved. This program and the accompanying materials\r
6 are licensed and made available under the terms and conditions of the BSD License\r
7 which accompanies this distribution. The full text of the license may be found at\r
8 http://opensource.org/licenses/bsd-license.php\r
9\r
10 THE PROGRAM IS DISTRIBUTED UNDER THE BSD LICENSE ON AN "AS IS" BASIS,\r
11 WITHOUT WARRANTIES OR REPRESENTATIONS OF ANY KIND, EITHER EXPRESS OR IMPLIED.\r
12\r
13**/\r
14\r
15//\r
16// Include common header file for this module.\r
17//\r
18#include "CommonHeader.h"\r
19\r
20#include "BaseLibInternals.h"\r
21\r
22/**\r
23 Returns the bit position of the highest bit set in a 32-bit value. Equivalent\r
24 to log2(x).\r
25\r
26 This function computes the bit position of the highest bit set in the 32-bit\r
27 value specified by Operand. If Operand is zero, then -1 is returned.\r
28 Otherwise, a value between 0 and 31 is returned.\r
29\r
30 @param Operand The 32-bit operand to evaluate.\r
31\r
32 @return Position of the highest bit set in Operand if found.\r
33 @retval -1 Operand is zero.\r
34\r
35**/\r
36INTN\r
37EFIAPI\r
38HighBitSet32 (\r
39 IN UINT32 Operand\r
40 )\r
41{\r
42 INTN BitIndex;\r
43\r
44 if (Operand == 0) {\r
45 return - 1;\r
46 }\r
47 for (BitIndex = 31; (INT32)Operand > 0; BitIndex--, Operand <<= 1);\r
48 return BitIndex;\r
49}\r