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dd453c4d 1/*
359fc2d2 2 * Copyright (C) the libgit2 contributors. All rights reserved.
dd453c4d 3 *
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4 * This file is part of libgit2, distributed under the GNU GPL v2 with
5 * a Linking Exception. For full terms see the included COPYING file.
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6 */
7
8#include <stdio.h>
9
10#include "sha1_lookup.h"
11#include "common.h"
67591c8c 12#include "oid.h"
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13
14/*
15 * Conventional binary search loop looks like this:
16 *
17 * unsigned lo, hi;
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18 * do {
19 * unsigned mi = (lo + hi) / 2;
20 * int cmp = "entry pointed at by mi" minus "target";
21 * if (!cmp)
22 * return (mi is the wanted one)
23 * if (cmp > 0)
24 * hi = mi; "mi is larger than target"
25 * else
26 * lo = mi+1; "mi is smaller than target"
27 * } while (lo < hi);
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28 *
29 * The invariants are:
30 *
31 * - When entering the loop, lo points at a slot that is never
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32 * above the target (it could be at the target), hi points at a
33 * slot that is guaranteed to be above the target (it can never
34 * be at the target).
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35 *
36 * - We find a point 'mi' between lo and hi (mi could be the same
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37 * as lo, but never can be as same as hi), and check if it hits
38 * the target. There are three cases:
dd453c4d 39 *
87d9869f 40 * - if it is a hit, we are happy.
dd453c4d 41 *
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42 * - if it is strictly higher than the target, we set it to hi,
43 * and repeat the search.
dd453c4d 44 *
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45 * - if it is strictly lower than the target, we update lo to
46 * one slot after it, because we allow lo to be at the target.
dd453c4d 47 *
87d9869f 48 * If the loop exits, there is no matching entry.
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49 *
50 * When choosing 'mi', we do not have to take the "middle" but
51 * anywhere in between lo and hi, as long as lo <= mi < hi is
87d9869f 52 * satisfied. When we somehow know that the distance between the
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53 * target and lo is much shorter than the target and hi, we could
54 * pick mi that is much closer to lo than the midway.
55 *
56 * Now, we can take advantage of the fact that SHA-1 is a good hash
57 * function, and as long as there are enough entries in the table, we
87d9869f 58 * can expect uniform distribution. An entry that begins with for
dd453c4d 59 * example "deadbeef..." is much likely to appear much later than in
87d9869f 60 * the midway of the table. It can reasonably be expected to be near
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61 * 87% (222/256) from the top of the table.
62 *
87d9869f 63 * However, we do not want to pick "mi" too precisely. If the entry at
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64 * the 87% in the above example turns out to be higher than the target
65 * we are looking for, we would end up narrowing the search space down
66 * only by 13%, instead of 50% we would get if we did a simple binary
87d9869f 67 * search. So we would want to hedge our bets by being less aggressive.
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68 *
69 * The table at "table" holds at least "nr" entries of "elem_size"
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70 * bytes each. Each entry has the SHA-1 key at "key_offset". The
71 * table is sorted by the SHA-1 key of the entries. The caller wants
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72 * to find the entry with "key", and knows that the entry at "lo" is
73 * not higher than the entry it is looking for, and that the entry at
74 * "hi" is higher than the entry it is looking for.
75 */
76int sha1_entry_pos(const void *table,
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77 size_t elem_size,
78 size_t key_offset,
79 unsigned lo, unsigned hi, unsigned nr,
80 const unsigned char *key)
dd453c4d 81{
bb88da7f 82 const unsigned char *base = (const unsigned char*)table;
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83 const unsigned char *hi_key, *lo_key;
84 unsigned ofs_0;
85
86 if (!nr || lo >= hi)
87 return -1;
88
89 if (nr == hi)
90 hi_key = NULL;
91 else
92 hi_key = base + elem_size * hi + key_offset;
93 lo_key = base + elem_size * lo + key_offset;
94
95 ofs_0 = 0;
96 do {
97 int cmp;
98 unsigned ofs, mi, range;
99 unsigned lov, hiv, kyv;
100 const unsigned char *mi_key;
101
102 range = hi - lo;
103 if (hi_key) {
104 for (ofs = ofs_0; ofs < 20; ofs++)
105 if (lo_key[ofs] != hi_key[ofs])
106 break;
107 ofs_0 = ofs;
108 /*
109 * byte 0 thru (ofs-1) are the same between
110 * lo and hi; ofs is the first byte that is
111 * different.
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112 *
113 * If ofs==20, then no bytes are different,
114 * meaning we have entries with duplicate
115 * keys. We know that we are in a solid run
116 * of this entry (because the entries are
117 * sorted, and our lo and hi are the same,
118 * there can be nothing but this single key
119 * in between). So we can stop the search.
120 * Either one of these entries is it (and
121 * we do not care which), or we do not have
122 * it.
123 *
124 * Furthermore, we know that one of our
125 * endpoints must be the edge of the run of
126 * duplicates. For example, given this
127 * sequence:
128 *
129 * idx 0 1 2 3 4 5
130 * key A C C C C D
131 *
132 * If we are searching for "B", we might
133 * hit the duplicate run at lo=1, hi=3
134 * (e.g., by first mi=3, then mi=0). But we
135 * can never have lo > 1, because B < C.
136 * That is, if our key is less than the
137 * run, we know that "lo" is the edge, but
138 * we can say nothing of "hi". Similarly,
139 * if our key is greater than the run, we
140 * know that "hi" is the edge, but we can
141 * say nothing of "lo".
142 *
143 * Therefore if we do not find it, we also
144 * know where it would go if it did exist:
145 * just on the far side of the edge that we
146 * know about.
dd453c4d 147 */
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148 if (ofs == 20) {
149 mi = lo;
150 mi_key = base + elem_size * mi + key_offset;
151 cmp = memcmp(mi_key, key, 20);
152 if (!cmp)
153 return mi;
154 if (cmp < 0)
155 return -1 - hi;
156 else
157 return -1 - lo;
158 }
159
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160 hiv = hi_key[ofs_0];
161 if (ofs_0 < 19)
162 hiv = (hiv << 8) | hi_key[ofs_0+1];
163 } else {
164 hiv = 256;
165 if (ofs_0 < 19)
166 hiv <<= 8;
167 }
168 lov = lo_key[ofs_0];
169 kyv = key[ofs_0];
170 if (ofs_0 < 19) {
171 lov = (lov << 8) | lo_key[ofs_0+1];
172 kyv = (kyv << 8) | key[ofs_0+1];
173 }
1e94df08 174 assert(lov < hiv);
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175
176 if (kyv < lov)
177 return -1 - lo;
178 if (hiv < kyv)
179 return -1 - hi;
180
181 /*
182 * Even if we know the target is much closer to 'hi'
183 * than 'lo', if we pick too precisely and overshoot
184 * (e.g. when we know 'mi' is closer to 'hi' than to
185 * 'lo', pick 'mi' that is higher than the target), we
186 * end up narrowing the search space by a smaller
187 * amount (i.e. the distance between 'mi' and 'hi')
188 * than what we would have (i.e. about half of 'lo'
87d9869f 189 * and 'hi'). Hedge our bets to pick 'mi' less
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190 * aggressively, i.e. make 'mi' a bit closer to the
191 * middle than we would otherwise pick.
192 */
193 kyv = (kyv * 6 + lov + hiv) / 8;
194 if (lov < hiv - 1) {
195 if (kyv == lov)
196 kyv++;
197 else if (kyv == hiv)
198 kyv--;
199 }
200 mi = (range - 1) * (kyv - lov) / (hiv - lov) + lo;
201
202#ifdef INDEX_DEBUG_LOOKUP
203 printf("lo %u hi %u rg %u mi %u ", lo, hi, range, mi);
204 printf("ofs %u lov %x, hiv %x, kyv %x\n",
87d9869f 205 ofs_0, lov, hiv, kyv);
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206#endif
207
208 if (!(lo <= mi && mi < hi)) {
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209 giterr_set(GITERR_INVALID, "Assertion failure. Binary search invariant is false");
210 return -1;
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211 }
212
213 mi_key = base + elem_size * mi + key_offset;
214 cmp = memcmp(mi_key + ofs_0, key + ofs_0, 20 - ofs_0);
215 if (!cmp)
216 return mi;
217 if (cmp > 0) {
218 hi = mi;
219 hi_key = mi_key;
220 } else {
221 lo = mi + 1;
222 lo_key = mi_key + elem_size;
223 }
224 } while (lo < hi);
bb88da7f 225 return -((int)lo)-1;
dd453c4d 226}
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227
228int sha1_position(const void *table,
229 size_t stride,
230 unsigned lo, unsigned hi,
231 const unsigned char *key)
232{
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233 const unsigned char *base = table;
234
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235 do {
236 unsigned mi = (lo + hi) / 2;
59547ce7 237 int cmp = git_oid__hashcmp(base + mi * stride, key);
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238
239 if (!cmp)
240 return mi;
241
242 if (cmp > 0)
243 hi = mi;
244 else
245 lo = mi+1;
246 } while (lo < hi);
247
248 return -((int)lo)-1;
249}