src/tools/clippy/tests/ui/floating_point_log.stderr

   1 error: logarithm for bases 2, 10 and e can be computed more accurately
   2   --> $DIR/floating_point_log.rs:10:13
   3    |
   4 LL |     let _ = x.log(2f32);
   5    |             ^^^^^^^^^^^ help: consider using: `x.log2()`
   6    |
   7    = note: `-D clippy::suboptimal-flops` implied by `-D warnings`
   8
   9 error: logarithm for bases 2, 10 and e can be computed more accurately
  10   --> $DIR/floating_point_log.rs:11:13
  11    |
  12 LL |     let _ = x.log(10f32);
  13    |             ^^^^^^^^^^^^ help: consider using: `x.log10()`
  14
  15 error: logarithm for bases 2, 10 and e can be computed more accurately
  16   --> $DIR/floating_point_log.rs:12:13
  17    |
  18 LL |     let _ = x.log(std::f32::consts::E);
  19    |             ^^^^^^^^^^^^^^^^^^^^^^^^^^ help: consider using: `x.ln()`
  20
  21 error: logarithm for bases 2, 10 and e can be computed more accurately
  22   --> $DIR/floating_point_log.rs:13:13
  23    |
  24 LL |     let _ = x.log(TWO);
  25    |             ^^^^^^^^^^ help: consider using: `x.log2()`
  26
  27 error: logarithm for bases 2, 10 and e can be computed more accurately
  28   --> $DIR/floating_point_log.rs:14:13
  29    |
  30 LL |     let _ = x.log(E);
  31    |             ^^^^^^^^ help: consider using: `x.ln()`
  32
  33 error: logarithm for bases 2, 10 and e can be computed more accurately
  34   --> $DIR/floating_point_log.rs:17:13
  35    |
  36 LL |     let _ = x.log(2f64);
  37    |             ^^^^^^^^^^^ help: consider using: `x.log2()`
  38
  39 error: logarithm for bases 2, 10 and e can be computed more accurately
  40   --> $DIR/floating_point_log.rs:18:13
  41    |
  42 LL |     let _ = x.log(10f64);
  43    |             ^^^^^^^^^^^^ help: consider using: `x.log10()`
  44
  45 error: logarithm for bases 2, 10 and e can be computed more accurately
  46   --> $DIR/floating_point_log.rs:19:13
  47    |
  48 LL |     let _ = x.log(std::f64::consts::E);
  49    |             ^^^^^^^^^^^^^^^^^^^^^^^^^^ help: consider using: `x.ln()`
  50
  51 error: ln(1 + x) can be computed more accurately
  52   --> $DIR/floating_point_log.rs:24:13
  53    |
  54 LL |     let _ = (1f32 + 2.).ln();
  55    |             ^^^^^^^^^^^^^^^^ help: consider using: `2.0f32.ln_1p()`
  56    |
  57    = note: `-D clippy::imprecise-flops` implied by `-D warnings`
  58
  59 error: ln(1 + x) can be computed more accurately
  60   --> $DIR/floating_point_log.rs:25:13
  61    |
  62 LL |     let _ = (1f32 + 2.0).ln();
  63    |             ^^^^^^^^^^^^^^^^^ help: consider using: `2.0f32.ln_1p()`
  64
  65 error: ln(1 + x) can be computed more accurately
  66   --> $DIR/floating_point_log.rs:26:13
  67    |
  68 LL |     let _ = (1.0 + x).ln();
  69    |             ^^^^^^^^^^^^^^ help: consider using: `x.ln_1p()`
  70
  71 error: ln(1 + x) can be computed more accurately
  72   --> $DIR/floating_point_log.rs:27:13
  73    |
  74 LL |     let _ = (1.0 + x / 2.0).ln();
  75    |             ^^^^^^^^^^^^^^^^^^^^ help: consider using: `(x / 2.0).ln_1p()`
  76
  77 error: ln(1 + x) can be computed more accurately
  78   --> $DIR/floating_point_log.rs:28:13
  79    |
  80 LL |     let _ = (1.0 + x.powi(3)).ln();
  81    |             ^^^^^^^^^^^^^^^^^^^^^^ help: consider using: `x.powi(3).ln_1p()`
  82
  83 error: ln(1 + x) can be computed more accurately
  84   --> $DIR/floating_point_log.rs:29:13
  85    |
  86 LL |     let _ = (1.0 + x.powi(3) / 2.0).ln();
  87    |             ^^^^^^^^^^^^^^^^^^^^^^^^^^^^ help: consider using: `(x.powi(3) / 2.0).ln_1p()`
  88
  89 error: ln(1 + x) can be computed more accurately
  90   --> $DIR/floating_point_log.rs:30:13
  91    |
  92 LL |     let _ = (1.0 + (std::f32::consts::E - 1.0)).ln();
  93    |             ^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^ help: consider using: `((std::f32::consts::E - 1.0)).ln_1p()`
  94
  95 error: ln(1 + x) can be computed more accurately
  96   --> $DIR/floating_point_log.rs:31:13
  97    |
  98 LL |     let _ = (x + 1.0).ln();
  99    |             ^^^^^^^^^^^^^^ help: consider using: `x.ln_1p()`
 100
 101 error: ln(1 + x) can be computed more accurately
 102   --> $DIR/floating_point_log.rs:32:13
 103    |
 104 LL |     let _ = (x.powi(3) + 1.0).ln();
 105    |             ^^^^^^^^^^^^^^^^^^^^^^ help: consider using: `x.powi(3).ln_1p()`
 106
 107 error: ln(1 + x) can be computed more accurately
 108   --> $DIR/floating_point_log.rs:33:13
 109    |
 110 LL |     let _ = (x + 2.0 + 1.0).ln();
 111    |             ^^^^^^^^^^^^^^^^^^^^ help: consider using: `(x + 2.0).ln_1p()`
 112
 113 error: ln(1 + x) can be computed more accurately
 114   --> $DIR/floating_point_log.rs:34:13
 115    |
 116 LL |     let _ = (x / 2.0 + 1.0).ln();
 117    |             ^^^^^^^^^^^^^^^^^^^^ help: consider using: `(x / 2.0).ln_1p()`
 118
 119 error: ln(1 + x) can be computed more accurately
 120   --> $DIR/floating_point_log.rs:42:13
 121    |
 122 LL |     let _ = (1f64 + 2.).ln();
 123    |             ^^^^^^^^^^^^^^^^ help: consider using: `2.0f64.ln_1p()`
 124
 125 error: ln(1 + x) can be computed more accurately
 126   --> $DIR/floating_point_log.rs:43:13
 127    |
 128 LL |     let _ = (1f64 + 2.0).ln();
 129    |             ^^^^^^^^^^^^^^^^^ help: consider using: `2.0f64.ln_1p()`
 130
 131 error: ln(1 + x) can be computed more accurately
 132   --> $DIR/floating_point_log.rs:44:13
 133    |
 134 LL |     let _ = (1.0 + x).ln();
 135    |             ^^^^^^^^^^^^^^ help: consider using: `x.ln_1p()`
 136
 137 error: ln(1 + x) can be computed more accurately
 138   --> $DIR/floating_point_log.rs:45:13
 139    |
 140 LL |     let _ = (1.0 + x / 2.0).ln();
 141    |             ^^^^^^^^^^^^^^^^^^^^ help: consider using: `(x / 2.0).ln_1p()`
 142
 143 error: ln(1 + x) can be computed more accurately
 144   --> $DIR/floating_point_log.rs:46:13
 145    |
 146 LL |     let _ = (1.0 + x.powi(3)).ln();
 147    |             ^^^^^^^^^^^^^^^^^^^^^^ help: consider using: `x.powi(3).ln_1p()`
 148
 149 error: ln(1 + x) can be computed more accurately
 150   --> $DIR/floating_point_log.rs:47:13
 151    |
 152 LL |     let _ = (x + 1.0).ln();
 153    |             ^^^^^^^^^^^^^^ help: consider using: `x.ln_1p()`
 154
 155 error: ln(1 + x) can be computed more accurately
 156   --> $DIR/floating_point_log.rs:48:13
 157    |
 158 LL |     let _ = (x.powi(3) + 1.0).ln();
 159    |             ^^^^^^^^^^^^^^^^^^^^^^ help: consider using: `x.powi(3).ln_1p()`
 160
 161 error: ln(1 + x) can be computed more accurately
 162   --> $DIR/floating_point_log.rs:49:13
 163    |
 164 LL |     let _ = (x + 2.0 + 1.0).ln();
 165    |             ^^^^^^^^^^^^^^^^^^^^ help: consider using: `(x + 2.0).ln_1p()`
 166
 167 error: ln(1 + x) can be computed more accurately
 168   --> $DIR/floating_point_log.rs:50:13
 169    |
 170 LL |     let _ = (x / 2.0 + 1.0).ln();
 171    |             ^^^^^^^^^^^^^^^^^^^^ help: consider using: `(x / 2.0).ln_1p()`
 172
 173 error: aborting due to 28 previous errors
 174