Instead of testing bytes one by one, we can use the following trick
from https://graphics.stanford.edu/~seander/bithacks.html:
haszero(v) = (v - 0x01010101) & ~v & 0x80808080
The subexpression v - 0x01010101, evaluates to a high bit set in any
byte whenever the corresponding byte in v is zero or greater than 0x80.
The sub-expression ~v & 0x80808080 evaluates to high bits set in bytes
where the byte of v doesn't have its high bit set (so the byte was less
than 0x80). Finally, by ANDing these two sub-expressions the result is
the high bits set where the bytes in v were zero, since the high bits
set due to a value greater than 0x80 in the first sub-expression are
masked off by the second.
Reviewed-by: Richard Henderson <rth@twiddle.net> Signed-off-by: Aurelien Jarno <aurelien@aurel32.net>