commands/pgp: Format code for grub_error() is incorrect

The format code is for a 32-bit int, but the argument, keyid, is declared as
a 64 bit int. The comment above says keyid is 32-bit. I'm not sure if the
comment or declaration is wrong, so force the display of a 64-bit int for now.

Signed-off-by: Glenn Washburn <development@efficientek.com>
Reviewed-by: Daniel Kiper <daniel.kiper@oracle.com>

diff --git a/grub-core/commands/pgp.c b/grub-core/commands/pgp.c
index bbf6871fe71f8fe56f1165e110949330e008b30c..5daa1e9d00c7dc0d4e5bbbaee4154d66d0b5b626 100644 (file)
--- a/grub-core/commands/pgp.c
+++ b/grub-core/commands/pgp.c
@@ -633,8 +633,8 @@ grub_verify_signature_real (struct grub_pubkey_context *ctxt,
   if (!sk)
     {
       /* TRANSLATORS: %08x is 32-bit key id.  */
-      grub_error (GRUB_ERR_BAD_SIGNATURE, N_("public key %08x not found"),
-                 keyid);
+      grub_error (GRUB_ERR_BAD_SIGNATURE,
+                 N_("public key %08" PRIxGRUB_UINT64_T " not found"), keyid);
       goto fail;
     }