user_only: compile everything with -fpie

We really need compile _all_ sources for user target with -fpie when
use --enable-user-pie.

It's regression introduced by commit add16157d72454.

Signed-off-by: Kirill A. Shutemov <kirill@shutemov.name>
Cc: Blue Swirl <blauwirbel@gmail.com>
Signed-off-by: Juan Quintela <quintela@redhat.com>
Signed-off-by: Blue Swirl <blauwirbel@gmail.com>

diff --git a/Makefile.user b/Makefile.user
index 907e74bd9eec7d7f395e0a67055e792c90988293..9e4f040e7cbc3eb5db7d128b5ccea2deeac2260a 100644 (file)
--- a/Makefile.user
+++ b/Makefile.user
@@ -2,10 +2,15 @@
 
 include ../config-host.mak
 include $(SRC_PATH)/rules.mak
+include config.mak
 
 .PHONY: all
 
-VPATH=$(SRC_PATH)
+# Do not take %.o from $(SRC_PATH), only %.c and %.h
+# All %.o for user targets should be built with -fpie, when
+# configured with --enable-user-pie, so we don't want to
+# take %.o from $(SRC_PATH), since they built without -fpie
+vpath %.c %.h $(SRC_PATH)
 
 QEMU_CFLAGS+=-I..
 

diff --git a/configure b/configure
index cf1db862549e6a08de3091bbb324f1c8062f54a1..d815c7aa90cc9de144fe09c5bb8b97da1bb7808b 100755 (executable)
--- a/configure
+++ b/configure
@@ -2652,3 +2652,6 @@ d=libuser
 mkdir -p $d
 rm -f $d/Makefile
 ln -s $source_path/Makefile.user $d/Makefile
+if test "$static" = "no" -a "$user_pie" = "yes" ; then
+  echo "QEMU_CFLAGS+=-fpie" > $d/config.mak
+fi