When using the macro le32_to_cpu(x), we need to correctly convert x to be
__le32 in case it is defined as u32 variable.
Signed-off-by: Oded Gabbay <oded.gabbay@gmail.com>
Reviewed-by: Tomer Tayar <ttayar@habana.ai>
mb(); \
(val) = *((u32 *) (uintptr_t) (addr)); \
if (mem_written_by_device) \
- (val) = le32_to_cpu(val); \
+ (val) = le32_to_cpu(*(__le32 *) &(val)); \
if (cond) \
break; \
if (timeout_us && ktime_compare(ktime_get(), __timeout) > 0) { \
(val) = *((u32 *) (uintptr_t) (addr)); \
if (mem_written_by_device) \
- (val) = le32_to_cpu(val); \
+ (val) = le32_to_cpu(*(__le32 *) &(val)); \
break; \
} \
if (sleep_us) \