One of the more common cases of allocation size calculations is finding the
size of a structure that has a zero-sized array at the end, along with memory
for some number of elements for that array. For example:
struct foo {
int stuff;
struct boo entry[];
};
instance = kvzalloc(sizeof(struct foo) + count * sizeof(struct boo), GFP_KERNEL);
Instead of leaving these open-coded and prone to type mistakes, we can now
use the new struct_size() helper:
instance = kvzalloc(struct_size(instance, entry, count), GFP_KERNEL);
This code was detected with the help of Coccinelle.
Signed-off-by: Gustavo A. R. Silva <gustavo@embeddedor.com>
Signed-off-by: David S. Miller <davem@davemloft.net>
if (clipt_size < CLIPT_MIN_HASH_BUCKETS)
return NULL;
- ctbl = kvzalloc(sizeof(*ctbl) +
- clipt_size*sizeof(struct list_head), GFP_KERNEL);
+ ctbl = kvzalloc(struct_size(ctbl, hash_list, clipt_size), GFP_KERNEL);
if (!ctbl)
return NULL;