btrfs: remove useless return value statement in split_node

At the point when we set 'ret = 0' it's guaranteed that the function is
going to return 0 so directly return 0. No functional changes.

Reviewed-by: Johannes Thumshirn <johannes.thumshirn@wdc.com>
Signed-off-by: Nikolay Borisov <nborisov@suse.com>
Reviewed-by: David Sterba <dsterba@suse.com>
Signed-off-by: David Sterba <dsterba@suse.com>

diff --git a/fs/btrfs/ctree.c b/fs/btrfs/ctree.c
index 778a6d580545b5e0fcde9a64220d41b35834d96a..60135f6e64410aa67992f4980a96f29d14a5ff49 100644 (file)
--- a/fs/btrfs/ctree.c
+++ b/fs/btrfs/ctree.c
@@ -3459,7 +3459,6 @@ static noinline int split_node(struct btrfs_trans_handle *trans,
                           (c_nritems - mid) * sizeof(struct btrfs_key_ptr));
        btrfs_set_header_nritems(split, c_nritems - mid);
        btrfs_set_header_nritems(c, mid);
-       ret = 0;
 
        btrfs_mark_buffer_dirty(c);
        btrfs_mark_buffer_dirty(split);
@@ -3477,7 +3476,7 @@ static noinline int split_node(struct btrfs_trans_handle *trans,
                btrfs_tree_unlock(split);
                free_extent_buffer(split);
        }
-       return ret;
+       return 0;
 }
 
 /*