BugLink: https://launchpad.net/bugs/1861972
The function snprintf() writes at most size bytes (including the
terminating null byte ('\0') to str. Now, We can guarantee that the
parameter of size is lager than the length of str to be formatting
including its terminating null byte. So it's unnecessary to minus 1
for the input parameter 'size'.
Signed-off-by: Guojia Liao <liaoguojia@huawei.com>
Signed-off-by: Huazhong Tan <tanhuazhong@huawei.com>
Signed-off-by: David S. Miller <davem@davemloft.net>
(cherry picked from commit
cdc37385e3abaf2704adf8bb15a2c14f04762d3d)
Signed-off-by: Ike Panhc <ike.pan@canonical.com>
Signed-off-by: Seth Forshee <seth.forshee@canonical.com>
pr_info("%s: %s\n", hns3_driver_name, hns3_copyright);
client.type = HNAE3_CLIENT_KNIC;
- snprintf(client.name, HNAE3_CLIENT_NAME_LENGTH - 1, "%s",
+ snprintf(client.name, HNAE3_CLIENT_NAME_LENGTH, "%s",
hns3_driver_name);
client.ops = &client_ops;