One of the more common cases of allocation size calculations is finding
the size of a structure that has a zero-sized array at the end, along
with memory for some number of elements for that array. For example:
struct msm_gem_submit {
...
struct {
...
} bos[0];
};
Make use of the struct_size() helper instead of an open-coded version
in order to avoid any potential type mistakes.
So, replace the following form:
sizeof(*submit) + ((u64)nr_bos * sizeof(submit->bos[0]))
with:
struct_size(submit, bos, nr_bos)
This code was detected with the help of Coccinelle.
Signed-off-by: Gustavo A. R. Silva <gustavo@embeddedor.com>
Signed-off-by: Rob Clark <robdclark@chromium.org>
uint32_t nr_cmds)
{
struct msm_gem_submit *submit;
- uint64_t sz = sizeof(*submit) + ((u64)nr_bos * sizeof(submit->bos[0])) +
- ((u64)nr_cmds * sizeof(submit->cmd[0]));
+ uint64_t sz = struct_size(submit, bos, nr_bos) +
+ ((u64)nr_cmds * sizeof(submit->cmd[0]));
if (sz > SIZE_MAX)
return NULL;