UefiCpuPkg/MicrocodeUpdateDxe: Fix coding style issues in INF file

[mirror_edk2.git] / StdLib / BsdSocketLib / ns_addr.c

/*\r
 * Copyright (c) 1986, 1993\r
 *  The Regents of the University of California.  All rights reserved.\r
 *\r
 * This code is derived from software contributed to Berkeley by\r
 * J.Q. Johnson.\r
 *\r
 * Portions copyright (c) 1999, 2000\r
 * Intel Corporation.\r
 * All rights reserved.\r
 *\r
 * Redistribution and use in source and binary forms, with or without\r
 * modification, are permitted provided that the following conditions\r
 * are met:\r
 *\r
 * 1. Redistributions of source code must retain the above copyright\r
 *    notice, this list of conditions and the following disclaimer.\r
 *\r
 * 2. Redistributions in binary form must reproduce the above copyright\r
 *    notice, this list of conditions and the following disclaimer in the\r
 *    documentation and/or other materials provided with the distribution.\r
 *\r
 * 3. All advertising materials mentioning features or use of this software\r
 *    must display the following acknowledgement:\r
 *\r
 *    This product includes software developed by the University of\r
 *    California, Berkeley, Intel Corporation, and its contributors.\r
 *\r
 * 4. Neither the name of University, Intel Corporation, or their respective\r
 *    contributors may be used to endorse or promote products derived from\r
 *    this software without specific prior written permission.\r
 *\r
 * THIS SOFTWARE IS PROVIDED BY THE REGENTS, INTEL CORPORATION AND\r
 * CONTRIBUTORS ``AS IS'' AND ANY EXPRESS OR IMPLIED WARRANTIES, INCLUDING,\r
 * BUT NOT LIMITED TO, THE IMPLIED WARRANTIES OF MERCHANTABILITY AND FITNESS\r
 * FOR A PARTICULAR PURPOSE ARE DISCLAIMED.  IN NO EVENT SHALL THE REGENTS,\r
 * INTEL CORPORATION OR CONTRIBUTORS BE LIABLE FOR ANY DIRECT, INDIRECT,\r
 * INCIDENTAL, SPECIAL, EXEMPLARY, OR CONSEQUENTIAL DAMAGES (INCLUDING, BUT\r
 * NOT LIMITED TO, PROCUREMENT OF SUBSTITUTE GOODS OR SERVICES; LOSS OF USE,\r
 * DATA, OR PROFITS; OR BUSINESS INTERRUPTION) HOWEVER CAUSED AND ON ANY\r
 * THEORY OF LIABILITY, WHETHER IN CONTRACT, STRICT LIABILITY, OR TORT\r
 * (INCLUDING NEGLIGENCE OR OTHERWISE) ARISING IN ANY WAY OUT OF THE USE OF\r
 * THIS SOFTWARE, EVEN IF ADVISED OF THE POSSIBILITY OF SUCH DAMAGE.\r
 *\r
 */\r
\r
#if defined(LIBC_SCCS) && !defined(lint)\r
static char sccsid[] = "@(#)ns_addr.c 8.1 (Berkeley) 6/7/93";\r
#endif /* LIBC_SCCS and not lint */\r
\r
#include <sys/param.h>\r
#include <netns/ns.h>\r
#include <stdio.h>\r
#include <string.h>\r
\r
static struct ns_addr addr, zero_addr;\r
\r
static void Field   (char *buf, u_char *out, int len);\r
static void cvtbase (long oldbase, int newbase, int input[], int inlen, unsigned char result[], int reslen);\r
\r
struct ns_addr\r
ns_addr(\r
  const char *name\r
  )\r
{\r
  char separator;\r
  char *hostname, *socketname, *cp;\r
  char buf[50];\r
\r
  (void)strncpy(buf, name, sizeof(buf) - 1);\r
  buf[sizeof(buf) - 1] = '\0';\r
\r
  /*\r
   * First, figure out what he intends as a field separtor.\r
   * Despite the way this routine is written, the prefered\r
   * form  2-272.AA001234H.01777, i.e. XDE standard.\r
   * Great efforts are made to insure backward compatability.\r
   */\r
  if ((hostname = strchr(buf, '#')) != NULL)\r
    separator = '#';\r
  else {\r
    hostname = strchr(buf, '.');\r
    if ((cp = strchr(buf, ':')) &&\r
        ((hostname && cp < hostname) || (hostname == 0))) {\r
      hostname = cp;\r
      separator = ':';\r
    } else\r
      separator = '.';\r
  }\r
  if (hostname)\r
    *hostname++ = 0;\r
\r
  addr = zero_addr;\r
  Field(buf, addr.x_net.c_net, 4);\r
  if (hostname == 0)\r
    return (addr);  /* No separator means net only */\r
\r
  socketname = strchr(hostname, separator);\r
  if (socketname) {\r
    *socketname++ = 0;\r
    Field(socketname, (u_char *)&addr.x_port, 2);\r
  }\r
\r
  Field(hostname, addr.x_host.c_host, 6);\r
\r
  return (addr);\r
}\r
\r
static void\r
Field(\r
  char *buf,\r
  u_char *out,\r
  int len\r
  )\r
{\r
  register char *bp = buf;\r
  int i, ibase, base16 = 0, base10 = 0, clen = 0;\r
  int hb[6], *hp;\r
  char *fmt;\r
\r
  /*\r
   * first try 2-273#2-852-151-014#socket\r
   */\r
  if ((*buf != '-') &&\r
      (1 < (i = sscanf(buf, "%d-%d-%d-%d-%d",\r
      &hb[0], &hb[1], &hb[2], &hb[3], &hb[4])))) {\r
    cvtbase(1000L, 256, hb, i, out, len);\r
    return;\r
  }\r
  /*\r
   * try form 8E1#0.0.AA.0.5E.E6#socket\r
   */\r
  if (1 < (i = sscanf(buf,"%x.%x.%x.%x.%x.%x",\r
      &hb[0], &hb[1], &hb[2], &hb[3], &hb[4], &hb[5]))) {\r
    cvtbase(256L, 256, hb, i, out, len);\r
    return;\r
  }\r
  /*\r
   * try form 8E1#0:0:AA:0:5E:E6#socket\r
   */\r
  if (1 < (i = sscanf(buf,"%x:%x:%x:%x:%x:%x",\r
      &hb[0], &hb[1], &hb[2], &hb[3], &hb[4], &hb[5]))) {\r
    cvtbase(256L, 256, hb, i, out, len);\r
    return;\r
  }\r
  /*\r
   * This is REALLY stretching it but there was a\r
   * comma notation separting shorts -- definitely non standard\r
   */\r
  if (1 < (i = sscanf(buf,"%x,%x,%x",\r
      &hb[0], &hb[1], &hb[2]))) {\r
    hb[0] = htons(hb[0]); hb[1] = htons(hb[1]);\r
    hb[2] = htons(hb[2]);\r
    cvtbase(65536L, 256, hb, i, out, len);\r
    return;\r
  }\r
\r
  /* Need to decide if base 10, 16 or 8 */\r
  while (*bp) switch (*bp++) {\r
\r
  case '0': case '1': case '2': case '3': case '4': case '5':\r
  case '6': case '7': case '-':\r
    break;\r
\r
  case '8': case '9':\r
    base10 = 1;\r
    break;\r
\r
  case 'a': case 'b': case 'c': case 'd': case 'e': case 'f':\r
  case 'A': case 'B': case 'C': case 'D': case 'E': case 'F':\r
    base16 = 1;\r
    break;\r
\r
  case 'x': case 'X':\r
    *--bp = '0';\r
    base16 = 1;\r
    break;\r
\r
  case 'h': case 'H':\r
    base16 = 1;\r
    /* fall into */\r
\r
  default:\r
    *--bp = 0; /* Ends Loop */\r
  }\r
  if (base16) {\r
    fmt = "%3x";\r
    ibase = 4096;\r
  } else if (base10 == 0 && *buf == '0') {\r
    fmt = "%3o";\r
    ibase = 512;\r
  } else {\r
    fmt = "%3d";\r
    ibase = 1000;\r
  }\r
\r
  for (bp = buf; *bp++; ) clen++;\r
  if (clen == 0) clen++;\r
  if (clen > 18) clen = 18;\r
  i = ((clen - 1) / 3) + 1;\r
  bp = clen + buf - 3;\r
  hp = hb + i - 1;\r
\r
  while (hp > hb) {\r
    (void)sscanf(bp, fmt, hp);\r
    bp[0] = 0;\r
    hp--;\r
    bp -= 3;\r
  }\r
  (void)sscanf(buf, fmt, hp);\r
  cvtbase((long)ibase, 256, hb, i, out, len);\r
}\r
\r
static void\r
cvtbase(\r
  long oldbase,\r
  int newbase,\r
  int input[],\r
  int inlen,\r
  unsigned char result[],\r
  int reslen\r
  )\r
{\r
  int d, e;\r
  long sum;\r
\r
  e = 1;\r
  while (e > 0 && reslen > 0) {\r
    d = 0; e = 0; sum = 0;\r
    /* long division: input=input/newbase */\r
    while (d < inlen) {\r
      sum = sum*oldbase + (long) input[d];\r
      e += (sum > 0);\r
      input[d++] = sum / newbase;\r
      sum %= newbase;\r
    }\r
    result[--reslen] = (u_char)sum; /* accumulate remainder */\r
  }\r
  for (d=0; d < reslen; d++)\r
    result[d] = 0;\r
}\r