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1[/
2 / Copyright (c) 2008 Eric Niebler
3 /
4 / Distributed under the Boost Software License, Version 1.0. (See accompanying
5 / file LICENSE_1_0.txt or copy at http://www.boost.org/LICENSE_1_0.txt)
6 /]
7
8[section:implementation Appendix D: Implementation Notes]
9
10[section:sfinae Quick-n-Dirty Type Categorization]
11
12Much has already been written about dispatching on type traits using
13SFINAE (Substitution Failure Is Not An Error) techniques in C++. There
14is a Boost library, Boost.Enable_if, to make the technique idiomatic.
15Proto dispatches on type traits extensively, but it doesn't use
16`enable_if<>` very often. Rather, it dispatches based on the presence
17or absence of nested types, often typedefs for void.
18
19Consider the implementation of `is_expr<>`. It could have been written
20as something like this:
21
22 template<typename T>
23 struct is_expr
24 : is_base_and_derived<proto::some_expr_base, T>
25 {};
26
27Rather, it is implemented as this:
28
29 template<typename T, typename Void = void>
30 struct is_expr
31 : mpl::false_
32 {};
33
34 template<typename T>
35 struct is_expr<T, typename T::proto_is_expr_>
36 : mpl::true_
37 {};
38
39This relies on the fact that the specialization will be preferred
40if `T` has a nested `proto_is_expr_` that is a typedef for `void`.
41All Proto expression types have such a nested typedef.
42
43Why does Proto do it this way? The reason is because, after running
44extensive benchmarks while trying to improve compile times, I have
45found that this approach compiles faster. It requires exactly one
46template instantiation. The other approach requires at least 2:
47`is_expr<>` and `is_base_and_derived<>`, plus whatever templates
48`is_base_and_derived<>` may instantiate.
49
50[endsect]
51
52[section:function_arity Detecting the Arity of Function Objects]
53
54In several places, Proto needs to know whether or not a function
55object `Fun` can be called with certain parameters and take a
56fallback action if not. This happens in _callable_context_ and
57in the _call_ transform. How does Proto know? It involves some
58tricky metaprogramming. Here's how.
59
60Another way of framing the question is by trying to implement
61the following `can_be_called<>` Boolean metafunction, which
62checks to see if a function object `Fun` can be called with
63parameters of type `A` and `B`:
64
65 template<typename Fun, typename A, typename B>
66 struct can_be_called;
67
68First, we define the following `dont_care` struct, which has an
69implicit conversion from anything. And not just any implicit
70conversion; it has a ellipsis conversion, which is the worst possible
71conversion for the purposes of overload resolution:
72
73 struct dont_care
74 {
75 dont_care(...);
76 };
77
78We also need some private type known only to us with an overloaded
79comma operator (!), and some functions that detect the presence of
80this type and return types with different sizes, as follows:
81
82 struct private_type
83 {
84 private_type const &operator,(int) const;
85 };
86
87 typedef char yes_type; // sizeof(yes_type) == 1
88 typedef char (&no_type)[2]; // sizeof(no_type) == 2
89
90 template<typename T>
91 no_type is_private_type(T const &);
92
93 yes_type is_private_type(private_type const &);
94
95Next, we implement a binary function object wrapper with a very
96strange conversion operator, whose meaning will become clear later.
97
98 template<typename Fun>
99 struct funwrap2 : Fun
100 {
101 funwrap2();
102 typedef private_type const &(*pointer_to_function)(dont_care, dont_care);
103 operator pointer_to_function() const;
104 };
105
106With all of these bits and pieces, we can implement `can_be_called<>` as
107follows:
108
109 template<typename Fun, typename A, typename B>
110 struct can_be_called
111 {
112 static funwrap2<Fun> &fun;
113 static A &a;
114 static B &b;
115
116 static bool const value = (
117 sizeof(no_type) == sizeof(is_private_type( (fun(a,b), 0) ))
118 );
119
120 typedef mpl::bool_<value> type;
121 };
122
123The idea is to make it so that `fun(a,b)` will always compile by adding
124our own binary function overload, but doing it in such a way that we can
125detect whether our overload was selected or not. And we rig it so that
126our overload is selected if there is really no better option. What follows
127is a description of how `can_be_called<>` works.
128
129We wrap `Fun` in a type that has an implicit conversion to a pointer to
130a binary function. An object `fun` of class type can be invoked as
131`fun(a, b)` if it has such a conversion operator, but since it involves
132a user-defined conversion operator, it is less preferred than an
133overloaded `operator()`, which requires no such conversion.
134
135The function pointer can accept any two arguments by virtue
136of the `dont_care` type. The conversion sequence for each argument is
137guaranteed to be the worst possible conversion sequence: an implicit
138conversion through an ellipsis, and a user-defined conversion to
139`dont_care`. In total, it means that `funwrap2<Fun>()(a, b)` will
140always compile, but it will select our overload only if there really is
141no better option.
142
143If there is a better option --- for example if `Fun` has an overloaded
144function call operator such as `void operator()(A a, B b)` --- then
145`fun(a, b)` will resolve to that one instead. The question now is how
146to detect which function got picked by overload resolution.
147
148Notice how `fun(a, b)` appears in `can_be_called<>`: `(fun(a, b), 0)`.
149Why do we use the comma operator there? The reason is because we are
150using this expression as the argument to a function. If the return type
151of `fun(a, b)` is `void`, it cannot legally be used as an argument to
152a function. The comma operator sidesteps the issue.
153
154This should also make plain the purpose of the overloaded comma operator
155in `private_type`. The return type of the pointer to function is
156`private_type`. If overload resolution selects our overload, then the
157type of `(fun(a, b), 0)` is `private_type`. Otherwise, it is `int`.
158That fact is used to dispatch to either overload of `is_private_type()`,
159which encodes its answer in the size of its return type.
160
161That's how it works with binary functions. Now repeat the above process
162for functions up to some predefined function arity, and you're done.
163
164[endsect]
165
166[/
167 [section:ppmp_vs_tmp Avoiding Template Instiations With The Preprocessor]
168
169 TODO
170
171 [endsect]
172]
173
174[endsect]