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1 [#repeated]
2 [section repeated]
3
4 [h1 Synopsis]
5
6 template <class P>
7 struct repeated;
8
9 This is a [link parser_combinator parser combinator].
10
11 [table Arguments
12 [[Name] [Type]]
13 [[`P`] [[link parser parser]]]
14 ]
15
16 [h1 Description]
17
18 It applies `P` on the input string repeatedly as long as `P` accepts the input.
19 The result of parsing is a sequence of the results of the individual
20 applications of `P`.
21
22 When `P` rejects the input for the first time, `repeated` still accepts the
23 input and the result of parsing is an empty sequence.
24
25 Here is a diagram showing how `repeated` works by example:
26
27 using int_token = token<int_>;
28
29 [$images/metaparse/repeated_diag1.png [width 70%]]
30
31 Further details can be found in the [link repetition Repetition] section
32 of the [link manual User Manual].
33
34 [h1 Header]
35
36 #include <boost/metaparse/repeated.hpp>
37
38 [h1 Expression semantics]
39
40 For any `p` parser the following are equivalent:
41
42 repeated<p>
43
44 foldl<
45 p,
46 /* unspecified empty sequence */,
47 boost::mpl::push_back<_2, _1>
48 >
49
50 [h1 Example]
51
52 #include <boost/metaparse/repeated.hpp>
53 #include <boost/metaparse/digit_val.hpp>
54 #include <boost/metaparse/start.hpp>
55 #include <boost/metaparse/string.hpp>
56 #include <boost/metaparse/get_result.hpp>
57
58 #include <boost/mpl/equal.hpp>
59 #include <boost/mpl/vector.hpp>
60 #include <boost/mpl/int.hpp>
61
62 using namespace boost::metaparse;
63
64 using digits = repeated<digit_val>;
65
66 static_assert(
67 boost::mpl::equal<
68 get_result<digits::apply<BOOST_METAPARSE_STRING("1234"), start>>::type,
69 boost::mpl::vector<
70 boost::mpl::int_<1>,
71 boost::mpl::int_<2>,
72 boost::mpl::int_<3>,
73 boost::mpl::int_<4>
74 >
75 >::type::value,
76 "the result of parsing should be the list of digit values"
77 );
78
79 static_assert(
80 boost::mpl::equal<
81 get_result<digits::apply<BOOST_METAPARSE_STRING("x"), start>>::type,
82 boost::mpl::vector<>
83 >::type::value,
84 "repeated should accept the input when it can't parse anything with digit_val"
85 );
86
87 [endsect]
88