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1 #include <iostream>
2 #include <limits>
3
4 #include <boost/rational.hpp>
5 #include <boost/safe_numerics/safe_integer.hpp>
6
7 int main(int, const char *[]){
8 // simple demo of rational library
9 const boost::rational<int> r {1, 2};
10 std::cout << "r = " << r << std::endl;
11 const boost::rational<int> q {-2, 4};
12 std::cout << "q = " << q << std::endl;
13 // display the product
14 std::cout << "r * q = " << r * q << std::endl;
15
16 // problem: rational doesn't handle integer overflow well
17 const boost::rational<int> c {1, INT_MAX};
18 std::cout << "c = " << c << std::endl;
19 const boost::rational<int> d {1, 2};
20 std::cout << "d = " << d << std::endl;
21 // display the product - wrong answer
22 std::cout << "c * d = " << c * d << std::endl;
23
24 // solution: use safe integer in rational definition
25 using safe_rational = boost::rational<
26 boost::safe_numerics::safe<int>
27 >;
28
29 // use rationals created with safe_t
30 const safe_rational sc {1, INT_MAX};
31 std::cout << "c = " << sc << std::endl;
32 const safe_rational sd {1, 2};
33 std::cout << "d = " << sd << std::endl;
34 std::cout << "c * d = ";
35 try {
36 // multiply them. This will overflow
37 std::cout << sc * sd << std::endl;
38 }
39 catch (std::exception const& e) {
40 // catch exception due to multiplication overflow
41 std::cout << e.what() << std::endl;
42 }
43
44 return 0;
45 }