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1 // Copyright (c) 2001-2010 Hartmut Kaiser
2 //
3 // Distributed under the Boost Software License, Version 1.0. (See accompanying
4 // file LICENSE_1_0.txt or copy at http://www.boost.org/LICENSE_1_0.txt)
5
6 // The main purpose of this example is to show how a single fusion sequence
7 // can be filled from a parsed input of the elements in different sequences
8
9 #include <boost/config/warning_disable.hpp>
10 #include <boost/mpl/print.hpp>
11 #include <boost/spirit/include/qi.hpp>
12 #include <boost/fusion/include/struct.hpp>
13 #include <boost/fusion/include/nview.hpp>
14 #include <boost/foreach.hpp>
15
16 namespace fusion = boost::fusion;
17 namespace qi = boost::spirit::qi;
18
19 ///////////////////////////////////////////////////////////////////////////////
20 namespace client
21 {
22 // Our employee struct
23 struct employee
24 {
25 std::string surname;
26 std::string forename;
27 int age;
28 double salary;
29 std::string department;
30 };
31
32 // define iterator type
33 typedef std::string::const_iterator iterator_type;
34
35 // This is the output routine taking a format description and the data to
36 // print
37 template <typename Parser, typename Sequence>
38 bool parse(std::string const& input, Parser const& p, Sequence& s)
39 {
40 iterator_type begin = input.begin();
41 return qi::parse(begin, input.end(), p, s);
42 }
43 }
44
45 // We need to tell fusion about our employee struct to make it a first-class
46 // fusion citizen. This has to be in global scope. Note that we don't need to
47 // list the members of our struct in the same sequence a they are defined
48 BOOST_FUSION_ADAPT_STRUCT(
49 client::employee,
50 (int, age)
51 (std::string, surname)
52 (std::string, forename)
53 (std::string, department)
54 (double, salary)
55 )
56
57 ///////////////////////////////////////////////////////////////////////////////
58 // that's the different types we need to reorder the attributes
59 typedef fusion::result_of::as_nview<client::employee, 2, 0>::type name_and_age;
60 typedef fusion::result_of::as_nview<client::employee, 1, 2, 4>::type names_and_salary;
61 typedef fusion::result_of::as_nview<client::employee, 2, 0, 3>::type name_age_and_department;
62
63 ///////////////////////////////////////////////////////////////////////////////
64 int main()
65 {
66 std::string str;
67
68 // some employees
69 client::employee john;
70 client::employee mary;
71 client::employee tom;
72
73 // print data about employees in different formats
74 {
75 // parse forename and age only
76 name_and_age johnview(fusion::as_nview<2, 0>(john));
77 bool r = client::parse(
78 "John, 25",
79 *(qi::char_ - ',') >> ", " >> qi::int_,
80 johnview);
81 if (r) {
82 std::cout << "Parsed: " << john.forename << ", " << john.age
83 << std::endl;
84 }
85
86 // parse surname, forename, and salary
87 names_and_salary maryview(fusion::as_nview<1, 2, 4>(mary));
88 r = client::parse(
89 "Higgins, Mary: 2200.36",
90 *(qi::char_ - ',') >> ", " >> *(qi::char_ - ':') >> ": " >> qi::double_,
91 maryview);
92 if (r) {
93 std::cout << "Parsed: " << mary.forename << ", " << mary.surname
94 << ", " << mary.salary << std::endl;
95 }
96
97 // parse forename, age, and department
98 name_age_and_department tomview(fusion::as_nview<2, 0, 3>(tom));
99 client::parse(
100 "Tom: 48 (Boss)",
101 *(qi::char_ - ':') >> ": " >> qi::int_ >> " (" >> *(qi::char_ - ')') >> ')',
102 tomview);
103 if (r) {
104 std::cout << "Parsed: " << tom.forename << ", " << tom.age
105 << ", " << tom.department << std::endl;
106 }
107 }
108
109 // now parse a list of several employees and print them all
110 std::vector<client::employee> employees;
111
112 // parse surname, forename, and salary for all employees
113 {
114 qi::rule<client::iterator_type, names_and_salary()> r =
115 *(qi::char_ - ',') >> ", " >> *(qi::char_ - ',') >> ", " >> qi::double_;
116
117 bool result = client::parse(
118 "John, Smith, 2000.50\n" "Mary, Higgins, 2200.36\n" "Tom, Taylor, 3200.00\n",
119 r % qi::eol, employees);
120
121 std::cout << "Parsed: " << std::endl;
122 BOOST_FOREACH(client::employee const& e, employees)
123 {
124 std::cout << e.forename << ", " << e.surname << ", " << e.salary
125 << std::endl;
126 }
127 }
128 return 0;
129 }
130